Question

a).x^2-3x+1=0
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Answer 1

x²-3x+1=0
a=1
b=-3
c=1
Δ=b²-4ac (4ac, adica 4·a·c)
Δ=(-3)²-4·1·1
Δ=9-4
Δ=5
5>0
$x_{1,2}= \frac{-b+sau- \sqrt{delta} }{2a}$
$x_{1} = \frac{-(-3)+ \sqrt{5} }{2} \\ x_{1}= \frac{3+ \sqrt{5} }{2}$
$x_{2} = \frac{-(-3)- \sqrt{5} }{2} \\ x_{2} = \frac{3- \sqrt{5} }{2}.$
Solutiile ecuatiei sunt $(\frac{3+ \sqrt{5} }{2} ; \frac{3- \sqrt{5} }{2}).$
Sper ca te-am ajutat! :)