Question

a) (x-3)²+(x +1 )²-(2x+1)×(2x-1)=
b) (2x+5)²- (3x-5)² + (2x+7)×(2x-7)=
c) (x+4)²-(2x-3)× (2x+3) + ( 2x+1)²=
d) ( 2x+3)²-2(x-3)×(x+3) + ( x-6 )×(x+6) - ( 2x-1)²=
e) (3x-1)×(3x+1)-(3x+1)²+(3x-1)²=
f) (3-2x)²-(2x+5)×(2x-3) + 4(x-2)²=
g) (4x-3)²-3(x+1)×(x-1)-2(2x-7)=

Ajutati-ma repede va rooog , am mare nevoie de ajutooor

Answer 1

Ca sa poti rezolva astfel de exercitii trebuie sa cunosti relatiile:
(a+b)²=a²+2ab+b²;
(a-b)²=a²-2ab+b²; 
a²-b²=(a+b)(a-b)


A) (x-3)²+(x +1 )²-(2x+1)×(2x-1)=
x²-6x+9+x²+2x+1-(4x²-1)=
2x²-4x+10-4x²+1=
-2x²-4x+11

b) (2x+5)²- (3x-5)² + (2x+7)×(2x-7)=
4x²+20x+25-(9x²-30x+25)+4x²-49=
4x²+20x+25-9x²+30x-25+4x²-49=
-x²+50x-49

c) (x+4)²-(2x-3)× (2x+3) + ( 2x+1)²=
x²+8x+16-(4x²-9)+4x²+4x+1=
x²+8x+16-4x²+9+4x²+4x+1=
x²+12x+26

d) ( 2x+3)²-2(x-3)×(x+3) + ( x-6 )×(x+6) - ( 2x-1)²=
4x²+12x+9-2(x²-9)+x²-36-(4x²-4x+1)=
4x²+12x+9-2x²+18+x²-36-4x²+4x-1=
-x²+16x-10

e) (3x-1)×(3x+1)-(3x+1)²+(3x-1)²=
9x²-1-(9x²+6x+1)+9x²-6x+1=
9x²-1-9x²-6x-1+9x²-6x+1=
9x²-12x-1

f) (3-2x)²-(2x+5)×(2x-3) + 4(x-2)²=
9-12x+4x²-(4x²-6x+10x-15)+4(x²-4x+4)=
9-12x+4x²-4x²+6x-10x+15+4x²-16x+16=
4x²-32x+40

g) (4x-3)²-3(x+1)×(x-1)-2(2x-7)= 
16x²-24x+9-3(x²-1)-4x+17=
16x²-24x+9-3x²+3-4x+17=
13x²-28x+29