Question

a)(x+3)(x-2)=x(x-5)+6;
b)(x+4)(2x+3)=(2x-5)(x-2)+22;
c)3x(3x-4)+25=(4x-1)(2x+5)+x^2;
d)x(4-x)=(3+x)(x+2)-2x^2+3;
e)x(x-3)+2(x^2+3)=(2-3x)(5-x)+10;
f)(x-1)(x+2)-(2-x)(3+x)=(2x-7)(x+4).
Va rog mult ajutatima dacă știți!!!

Answer 1

a)

(x+3)(x-2)=x(x-5)+6

x²-2x+3x-6=x²-5x+6

-2x+3x-6=-5x+6

x-6=-5x+6

x-6+5x-6=0

6x-12=0

x-2=0 / +2

x=2

b)

(x+4)(2x+3)=(2x-5)(x-2)+22

2x²+3x+8x+12=2x²-4x-5x+10+22

3x+8x+12=-4x-5x+10+22

11x+12=-9x+32

11x+12x+9x=0

20x-20=0

x-1=0/+1

x=1

c)

3x(3x-4)+25=(4x-1)(2x+5)+x²

9x²-12x+25=8x²+20x-2x-5+x²

9x²-12x+25=9x²+18x-5

-12x+25=18x-5

-12x+25-18x+5=0

-30x+30=0

x-1=0/+1

x=1

d)

x(4-x)=(3+x)(x+2)-2x²+3

4x-x²=3x+6+x²+2x-2x²+3

4x-x²=5x+9-x²

4x=5x+9

4x-5x=9

-x=9

x=-9

e)

x(x-3)+2(x²+3)=(2-3x)(5-x)+10

x²-3x+2x²+6=10-2x-15x+3x²+10

3x²-3x+6=20-17x+3x²

-3x+6=20-17x

-3x+6-20+17x=0

14x-14=0

x-1=0/+1

x=1

f)

(x-1)(x+2)-(2-x)(3+x)=(2x-7)(x+4)

x²+2x-x-2-(6+2x-3x-x²)=2x²+8x-7x-28

x²+2x-x-2-(6-x-x²)=2x²+x-28

x²+2x-x-2-6+x+x²=2x²+x-28

2x²+2x-8=2x²+x-28

2x-8=x-28

2x-8-x+28=0

x+20=0/-20

x=-20