Question

A)(x-y)(x+y)=
b)(2a+b)(20-b)=
c)(y-3)(y+3)=
d)(x+4)(x-4)=
e)(6+a)(6-a)=
f)(1-c)(1+c=
g)(2a-1)(20+1=

Answer 1

a) (x-y)(x+y)=$x^{2} - y^{2}$

b)(20+b)(20-b)=400-$b^{2}$

c)(y-3)(y+3)=$y^{2}$-9

d)(x+4)(x-4)=$x^{2}$-16

e)(6+a)(6-a)=36-$a^{2}$

f)(1-c)(1+c)=1-$c^{2}$

g)(2a-1)(2a+1)=$4a^{2}$-1

Sper ca te-am ajutat! :)