Question

A={x€z||x|<sau=3}
A={x€R||2x|<2}​

Answer 1

Răspuns:

Explicație pas cu pas:

IxI ≤ 3

-3 ≤ x ≤ 3

A = {-3, -2. -1, 0, 1, 2, 3}

______________

I2xI < 2

-2 < 2x < 2

-1 < x < 1

A = (-1, 1)

Answer 2

A={x∈Z | |x|≤3}

|x|≤3

-3≤x≤3

x∈{-3,-2,-1,0,1,2,3}

A={-3,-2,-1,0,1,2,3}

A={x∈R | |2x|<2}

|2x|<2

2|x|<2

|x|<1

-1<x<1

x∈(-1,1)

A=(-1,1)