Question

a) x²-6x+9
b) x²-8x+16
c) x²-10x+25
d) x²-12x+36
e) 16x²-8x+1
f) 25x²-10x+1
g) 25x²-20x+4
h)25x²-60x+36
i) 4x²-28x+49
j) 25-70x+49x²

Ajutor va rog repedee dau coroana

Answer 1

Bănuiesc că vrei să rezolvi ecuațiile
Ne vom folosi de formulele
delta=b^2-4ac
x1,2=( -b + sau - radical din delta)/2a
unde a, b și c sunt coeficienții polinomului astfel:
a-coeficientul de lângă x^2
b - coeficientul de lângă x
c - termenul liber

a) x²-6x+9=0
delta=36-36=0
x1,2=6/2=3

b)x²-8x+16=0
delta=64-64=0
x1,2=8/2=4

c)x²-10x+25=0
delta=100-100=0
x1,2=10/2=5

d) x²-12x+36=0
delta=144-144=0
x1,2=12/2=6

e) 16x²-8x+1=0
delta=64-64=0
x1,2=8/32=1/4

f) 25x²-10x+1=0
delta=100-100=0
x1,2=10/50=1/5

g) 25x²-20x+4=0
delta=400-400=0
x1,2=20/50=2/5

h)25x²-60x+36=0
delta=360-360=0
x1,2=60/50=6/5

i) 4x²-28x+49=0
delta=784-784=0
x1,2=28/8=7/2

j)25-70x+49x²=0
delta=4900-4900=0
x1,2=70/50=7/5

Answer 2

   
[tex]\text{Vom folosi formula: } ~~\boxed{a^2 -2ab + b^2 = (a-b)^2}\\\\ a) ~~x^2-6x+9= x^2 -2\cdot x\cdot 3+3^2 =(x-3)^2\\\\ b) ~~x^2-8x+16 =x^2 -2\cdot x \cdot 4+4^2 =(x-4)^2\\ \\ c) ~~x^2-10x+25= x^2 -2\cdot x\cdot 5 +5^2 =(x-5)^2\\ \\ d) ~~x^2-12x+36 =x^2 -2\cdot x\cdot 6 +6^2 =(x-6)^2\\ \\ e) ~~16x^2-8x+1= (4x)^2 -2\cdot 4x \cdot 1 + 1^2 =(4x-1)^2\\\\ f) ~~25x^2-10x+1 = (5x)^2 -2\cdot 5x \cdot 1 + 1^2 =(5x-1)^2[/tex]

[tex]g)~~ 25x^2-20x+4= (5x)^2 -2\cdot 5x \cdot 2 + 2^2 =(5x-2)^2\\\\ h)~~25x^2-60x+36= (5x)^2 -2\cdot 5x \cdot 6 + 6^2 =(5x-6)^2\\\\ i) ~~4x^2-28x+49= (2x)^2 -2\cdot 2x \cdot 7 + 7^2 =(2x-7)^2\\\\ j) ~~25-70x+49x^2=5^2 - 2\cdot 5\cdot 7x + (7x)^2 = (5-7x)^2[/tex]