Question

a) x²+7X+12=0
b) x² + 4x + 4 =0​

Answer 1

a)

x²+7x+12 = 0

x²+4x+3x+12 = 0

x(x+4)+3(x+4) = 0

(x+4)(x+3) = 0

⇒ x ∈ {-4, -3}

b)

x²+4x+4 = 0

(x+2)² = 0

⇒ x = -2

Answer 2

Răspuns:

Explicație pas cu pas:

a.

x^2 + 7 x + 12 = x^2 +3x +4x +12= x ( x +3) +4  (x + 3)= (x+3) (x+4)

b.

x^2 + 4x + 4 =x^2 + 2x + 2x = 4 = x ( x+2) + 2 ( x+2) = (x=2) ( x+2) =( x+2 )^2