Question

A2.Functiile Fk:R→ R, k apartine {1, 2, 3},

F1(x)=x/2+3/16·sin(4x/3)-3radical din 3/16·cos(4x/3),

F2(x)=x/2-3/4·sin(pi/6-2x/3),

F3(x)=x/2-3/8·cos(pi/6+4x/3), sunt primitive ale functiei

f:R→ R, f(x)=cos^2(pi/6-2x/3) ?

Answer 1

Răspuns:

$F1(x)=\frac{x}{2} +\frac{3}{16} * sin \frac{4x}{3} -\sqrt{3} \\\\F1(x) =\frac{x}{1} + \frac{3}{8} * sin$

Sper ca te-am ajutat!