Question

a8 va rog cum se rezolva ​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns:I

Explicație pas cu pas:

I. lxl≤3  x∈[-3,3]

I=[-3,3]

J.lx+1l≥3

x+1≤-3   x≤-4

x+1≥3  x≥2

x∈(-∞,-4]U[2,+∞)

J=(-∞,-4]U[2+∞)

k.3/2<lx+1/2l

x+1/2<-3/2

x<-3/2-1/2

x< -2 x∈(-∞ -2)

x+1/2>3/2

x>3/2-1/2   x>2/2=1

x∈(-∞,-2)U(1,+∞)=K

b)IUJ=[-3,3]U(-oo, -4]U[2,+oo)=(-oo,-4]U[-3,+oo)

JUK=(-oo,-4]U[2+oo)U(-oo,-2)U(1,+oo)=(-oo ,-2)U(1,+oo)

InK=[-3,3]n(-oo,-2)U(1,+oo)=[-3,2)U(1,3]

InJ=[-3,3]n(-oo,-4]U[2,+oo)=[-4,-3]U[2,3]

InJnk=[-4,-3]U[2,3]n(-oo, -2)U(1,+oo)=[-4,-3]U[2,3]

I-J=[-3,3]\(oo,-4]U[2,+oo)=[-3,2)

K\J=(-oo,-2)U(1,+oo)\(-oo,-4]U[2,+oo)=(-4,-2)U(1,2)

R\J=R\(-oo,-4]U[2<+oo)=(-4,2)=CJ(rR)