Question

abc : bc=4, rest bc-8
ps:toate sunt cu bara deasupra
dau COROANA

Answer 1

[tex]\overline{abc}:\overline{bc}=4,r=\overline{bc}-8\\ \text{Din teorema impartirii cu rest avem ca:}\\ \overline{abc}=4\cdot\overline{bc}+\overline{bc}-8\\ 100\cdot a+\overline{bc}=5\cdot \overline{bc}-8\\ 100\cdot a=4\cdot \overline{bc}-8\\ \text{Tinem cont de faptul ca :}\\ 4\cdot \overline{bc}-8 \leq 388\Rightarrow a\in \{1,2,3\}\\ \text{Acum ii dam valori lui a:}\\ pt.\ a=1\Rightarrow \overline{bc}=27\\ pt.\ a=2\Rightarrow \overline{bc}=52\\ pt.\ a=3\Rightarrow \overline{bc}=77\\ [/tex]
$S:\overline{abc}\in \{127, 252,377\}$