Question

(abc +bca+cab) div cu 37
(grupurile de litere au bara deasupra)

Answer 1

$\overline{abc}+\overline{bca}+\overline{cab}=$

$=100a+10b+c+100b+10c+a+100c+10a+b=$

$=111a+111b+111c=$

$=111(a+b+c)=$

$=37*3(a+b+c)$

=>$( \overline{abc}+\overline{bca}+\overline{cab})$⋮37

Answer 2

Rezolvarea este anexata !
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