Question

ABC triunghi dreptunghic in a , AB =8 cm BC = 10 cm AD_|_BC D face parte din BC , aflati Pabc , Aabc si Ad

Answer 1

ABC triunghi dr => Teorema lui Pitagora:
BC^2=AB^2+AC^2
AC^2=BC^2-AB^2= 10^2-8^2= 100-64=36
=> AC=√36=6cm
Pabc= AB+AC+BC= 8+6+10=24 cm
Aabc=AB*AC/2=8*6/2= 42/2=21 cm^2
AD= AB*AC/BC= 8*6/10=42/10=4,2 cm