Question

ABCD-patrat;
AB=24cm;  MD perpendicular (ABC);
MD= 12√2cm;
AC intersectia BD={O}
Calculati: MB, MC. MD, MO=?

Va rog ajutati-ma cat mai repede VA ROG!!!!!

Answer 1

ab=bc=cd=da=24  
mo=dc/2    mo=24/2    mo=12
in triunghiul dom dreptunghic in o=90 grade avem;
do patrat=dm patrat-om patrat =>do=12
triunghiul dcb isoscel , co =inaltime => db=24
in triunghiul bdc isoscel    dm=inaltime  => mb=mc=bc/2=12
md=dcpatrat-mcpatrat    md=rd432   md=12rd3

Answer 2

Triunghiul MDC dreptunghic
MD=12 $\sqrt{2}$
DC=24
T Pitagora=>MC^2=MD^2+DC^2=288+576
=>MC=12$\sqrt{6}$

Tringhiul MDB dreptunghic
DB=24$\sqrt{2}$
MD=12$\sqrt{2}$
T Pitagora=>MB^2=DB^2+MD^2=288+1152
MB=12$\sqrt{10}$

Tringhiul MDO dreptunghic
MD=DO=12$\sqrt{2}$
T Pitagora=>MO^2=MD^2+MO^2=288+288
=>MO=24