Question

ABCD patrat
perimetrul ABCD este 1 m
arria=?

Answer 1

$P_{ABCD}=4*l=1\Rightarrow l=0.25$
$A_{ABCD}=l^{2}=0,25^{2}=0.0625 m^{2}$

Answer 2

$P_{\Box_{ABCD}}=1 \ m^2 \\ P=4l \\ \Rightarrow l= \frac{P_{\Box_{ABCD}}}{4} = \frac{1 \ m^2}{4} \\ \Rightarrow l=0,25 \ m \\ A=l \cdot l=l^2 \\ \Rightarrow A=(0,25 \ m)^2=(0,25 \ m ) \cdot (0,25 \ m) \\ \Rightarrow \boxed{A_\Box_{ABCD}=0,0625 \ m^2}.$