Question

ABCD trapez dreptunghic , AB paralel CD , AC perpendicular BC , mas unghi =60 si AD = 24, care este peimetrul ABCD ??

Answer 1

ducem CE_I_ AB
sin 60⁰ = CE/CB
√3/2=24/CB
CB=48/√3=48√3/3=16√3

sin 30⁰ = EB/CB
1/2=EB/16√3
EB=16√3/2=8√3

CE²=AE * EB
24²=AE*8√3
AE=576/8√3=72√3/3=24√3
DC= AE=24√3
P=AD+DC+CB+AB
P=24+24√3+16√3+(24√3+8√3)=24+72√3=24(1+3√3) cm