Question

ABCDA'B'C'D' PRISMA TRIUNGHIULARA REGULATA AB=4cm,AA'=2√6cm,calculati a)d(C'(A'C)) va rog multtt

Answer 1

ΔCC'A' dreptunghic
A'C²=C'C²+C'A'²
A'C²=(2√6)²+4²=24+16=40
A'C=2√10
d(C'(A'C))=C'M inaltimea triunghiului
aplicam teorema catetei
C'C²=CM·CA'
24=CM·2√10
CM=6√10/5
MA'=2√10-6√10/5=4√10/5
aplicam teorema inaltimii
C'M²=CM·MA'
C'M²=6√10/5·4√10/5
C'M=4√15/5