Question

Aceasta este problema. As vrea rezolvarea completa, va rog!

Answer 1

$\overline {2,1(a)}+\overline{2,a(1)}=\overline{a,1(2)}+\overline{1,a(2)}$

$\frac{\overline{21a}-21}{90} +\frac{\overline{2a1}-\overline{2a}}{90} =\frac{\overline{a12}-\overline{a1}}{90} +\frac{\overline{1a2}-\overline{1a}}{90}$

• Avem acelasi numitor, il eliminam si scriem numerele in baza 10, vom obtine:

200+10+a-21+200+10a+1-20-a=100a+10+2-10a-1+100+10a+2-10-a

411-41+10a=99a+103

267=89a

a=267:89=3

a=3