Question

aceste 2 ex va rog frumos ​

Answer 1

Răspuns:

$n = \frac{4}{3} - \frac{4}{3} \times ( \frac{4}{3} - (0.(3)) ^{2} ) \div 4 \frac{8}{9} = \\ n = \frac{4}{3} - \frac{4}{3} \times ( \frac{4}{3} - ( \frac{1}{3} ) ^{2} ) \div \frac{44}{9 } \\ n = \frac{4}{3} - \frac{4}{3} \times ( \frac{4}{3} - \frac{1}{9} ) \div \frac{44}{9} \\ n = \frac{4}{3} - \frac{4}{3} \times \frac{12 - 1}{9} \div \frac{44}{9} \\ n = \frac{4}{3} - \frac{4}{3} \times \frac{11}{9} \div \frac{44}{9} \\ n = \frac{4}{3} - \frac{44}{27} \div \frac{44}{9} \\ n = \frac{4}{3} - \frac{44}{27} \times \frac{9}{44} \\ n = \frac{4}{3} - \frac{1}{3} = \frac{3}{3} = 1$