Question

Aceste 2 probeleme va. rog​

Answer 1

CORONIȚĂ?

Sper ca te-am fost de folos!!

Answer 2

1.

$\sqrt{ {3}^{2} } = 3$

$\sqrt{ {3}^{2} \times 5} = 3 \sqrt{5}$

$\sqrt{ {5}^{3} } = \sqrt{ {5}^{2} \times 5} = 5 \sqrt{5}$

$\sqrt{12} = \sqrt{4 \times 3} = \sqrt{ {2}^{2} \times 3} = 2 \sqrt{3}$

$\sqrt{24} = \sqrt{4 \times 6} = \sqrt{ {2}^{2} \times 6} = 2 \sqrt{6}$

$\sqrt{27} = \sqrt{ {3}^{3} } = \sqrt{ {3}^{2} \times 3} = 3 \sqrt{3}$

2.

$2 \sqrt{3} = \sqrt{ {2}^{2} \times 3} = \sqrt{4 \times 3} = \sqrt{12}$

$3 \sqrt{5} = \sqrt{ {3}^{2} \times 5} = \sqrt{9 \times 5} = \sqrt{45}$

$- 5 \sqrt{2} = - \sqrt{ {5}^{2} \times 2} = - \sqrt{25 \times 2} = - \sqrt{50}$

$2 \sqrt{2} = \sqrt{ {2}^{2} \times 2} = \sqrt{ {2}^{3} } = \sqrt{8}$

$3 \sqrt{3} = \sqrt{ {3}^{2} \times 3} = \sqrt{ {3}^{3} } = \sqrt{27}$

$6 \sqrt{11} = \sqrt{ {6}^{2} \times 11} = \sqrt{36 \times 11} = \sqrt{396}$

$- 4 \sqrt{6} = - \sqrt{ {4}^{2} \times 6} = - \sqrt{16 \times 6} = - \sqrt{96}$