Question

Aceste 2 probleme. Dau puncte cu nemiluita

Answer 1

3. b)

2019:(n+4)=9 rest n+3

2019=9•(n+4)+n+3)

2019=9n+36+n+3

2019=10n+39

10n=2019-39

n=1980:10

n=198; n+4=202; n+3=201

impartitorul=202

verificare: 2019:202=9 rest 201

               2019=9•202+201 (A)

4.

a+b+c+d=2019

b=8+2a

c=8+a+b=8+a+(8+2a);

c=16+3a

d=c-b-8=16+3a-8-2a-8

d=a

=> a+b+c+d=a+(8+2a)+16+3a+a

7a+24=2019

7a=2019-24

a=1995:7

a=285

b=8+2•285=8+570

b=578

c=8+(285+578)=8+863

c=871

d=285; sau d=871-578-8=285

285+578+871+285=2019