Question

Aceste exercițiu, va rog!! ​

Answer 1

Explicatie pas cu pas

Answer 2

${2}^{2002} + ( {2}^{2} ) ^{1001} = {2}^{n}$

${2}^{2002} + 2 ^{2002} = {2}^{n}$

$2 \times {2}^{2002} = {2}^{n}$

$2 {}^{2003} = 2 {}^{n}$

=>n=2003