Question

Acidul acetic din 60 ml solutie se neutralizeaza cu 30 ml solutie de hidroxid de caldiu 2M. Numarul de moli de acid a fost?

Answer 1

1. Afli md din Cm : Cm=md/M*Vs =>md=Cm*M*Vs=2*74*0.03=4.44g 2. Afli nr de moli de Ca(OH)2:
n=m/M=4.44/74=0.06 moli Ca(OH)2
3. Afli din reacție nr moli de CH3-COOH:
2CH3-COOH + Ca(OH)2 ---> (CH3-COO)2Ca + 2H2O
2 moli..........1mol
x=0.12mol................0.06mol