Question

Adevarat sau fals?
Daca √abc cu bara deasupra=31, atunci √a+b+c=4?

Answer 1

√abc = 31                 atunci  abc= 31² 
abc = 961 
a=9            b = 6               c = 1 
√(a +b +c ) = √( 9 + 6 + 1) = √16 = 4   adevarat

Answer 2

$\sqrt{abc} =31$ ⇒ $abc = 31^{2}.$
$abc= 961.$
$\sqrt{a+b+c} = 4$ ⇒ $a+b+c = 16.$ $9+6+1=16$. ⇒ $\sqrt{9+6+1} = 4.$