Question

aduceti la forma cea mai simpla:
a)3√2(2+√2)-5(3,5-√6)+11÷(7-1,5)
b)2
—0,25+78÷4-8√5:√5-3·7√2
5

√radical.La punctul b) e doi supra lui 5 inmultit cu 0,25

Answer 1

a)3√2(2+√2)-5(3,5-√6)+11÷(7-1,5)=
=6√2+6-17,5+5√6+11÷5,5=
=6√2-11,5+5√6+2=
=6√2-9,5+5√6


b)2/5 ×0,25+78÷4-8√5:√5-3·7√2=
=0,1+19,5-8-21√2=
=11,6-21√2

Answer 2

a)
3√2(2+√2)-5(3,5-√6)+11(:7-1,5)=
=6√2+3√2x√2-17,5+5√6+11:5,5=
=6√2+3√4-17,5+5√6+2=
=6√2+3x2-17,5+5√6+2=
=6√2+6-17,5+5√6+2=
=6√2+5√6-11,5+2=
=6√2+5√6-9,5


b)2/5 ×0,25+78:4-8√5:√5-3·7√2=
=0,4x0,25+19,5-8-21√2=
=0,1+19,5-8-21√2=
=19,6-8-21√2=
=11,6-21√2