Question

Aduceti la forma cea nai simpla expresia -(a-5)(a+3)-(1-a)la puterea a două
B) (x-1)(x-2)-(x-4) la puterea a doua

Answer 1

[tex]a)(a-4)(a+3)-(1-a)^2=\\ a^2-4a+3a-12-1+2a-a^2=a-13\\ b)(x-1)(x-2)-(x-4)^2=\\ x^2-x-2x+2-x^2+8x-16=5x-14 [/tex]

Answer 2

__________________________B.)(x-1)(x-2)-(x-4)^2=x^2-2x-x+2-(x^2-8x+16)=x^2-3x+2-x^2+8x-16=x^2-x^2+8x-3x-16+2=0+5x-14=5x-14._______________ A.)-(a-5)(a+3)-(1-a)^2=-(a^2+3a-5a-15)-(1^2-2a•1+a^2)=-(a^2-2a-15)-(1-2a+a^2)=-a^2+2a+15-1+2a-a^2=-2a^2+4a+14.da eu cred ca ai scris din greseala minusul din fata la "-(a-5)".si atunci dadea:______ reluam de la -(a^2-2a-15)-(1-2a+a^2) cum nu ar fi minusul acela in fata si obtinem: a^2-2a-15-(1-2a+a^2)=a^2-2a-15-1+2a-a^2=a^2-a^2-2a+2a-15-1=0+0-16=-16