Question

aduceti la o formula mai simpla
$(3b^{-2} - 2a^{-1}) inmultit ( \frac{b^{-2}}{3^{-1}}+\frac{1}{2^{-1}a})inmultit (4a^{-2}+\frac{b^{-4}}{3^{-2}})$

Answer 1

3*1/b-2*1/a)*(3/b^2+2/a)*(4/a^2+9/b^4)=

3/b^2-2/a)*(3/b^2+2/a)*(4/a^2+9/b^4)=

9/b^4+6/ab-4/a^2-6/ab)*(4/a^2+9/b^4)=

9/b^4-4/a^2)*(4/a^2+9/b^4)=

81/b^8-16/a^4