Question

Adunarea fractiilor cu putreri: 2^11+2^11=? 3^7+3^7+3^7=?

Answer 1

Răspuns:

a). = 2 la 11(1+1)=2x 2 la 11

b).  =3 la7(1+1+1)=3x 3 la 7

Explicație pas cu pas:

Answer 2

$2^{11}+2^{11}=2^{11}(1+1)=2^{11}*2^{1}=2^{11+1}=2^{12}$

$3^{7}+3^{7}+3^{7}=3^{7}(1+1+1)=3^{7}*3^{1}=3^{7+1}=3^{8}$