Question

afati 4 nr nat consecutive stiind ca impartind suma lor la 17 obtinem catul 12 si restul 6 va roog urgent

Answer 1

(a+a+1+a+2+a+3):17= 12, rest 6
4a+6= 12*17+6
4a+6= 204+6
4a+6= 210
4a= 210-6a= 204a= 204:4a=51 
nr sunt: 51,52,53,54

Answer 2

(a+a+1+a+2+a+3):17=12(r6)
a+a+1+a+2+a+3=17*12+6
a+a+1+a+2+a+3=204+6
4*a+6=210
4*a=210-6
4*a=204
a=204:4
a=51
a+1=52
a+2=53
a+3=54