Question

afati media aritmetica si geometrica din;
a=(7-√2)la puterea2
b=(7+√2)la puterea2 va rog mult

Answer 1

a=(7-√2)²=49+2-14√2=51-14√2
b=(7+√2)²=49+2+14√2=51+14√2

ma=(a+b)/2=(51-14√2+51+14√2)/2=51
mg=√(51-14√2)(51+14√2)=√(2601-392)=√2209=47

Answer 2

$\displaystyle a=(7- \sqrt{2} )^2=7^2-2 \cdot 7 \cdot \sqrt{2} + \sqrt{2} ^2=49-14 \sqrt{2} +2=51-14 \sqrt{2} \\ b=(7+ \sqrt{2} )^2=7^2+2 \cdot 7 \cdot \sqrt{2} + \sqrt{2} ^2=49+14 \sqrt{2} +2=51+14 \sqrt{2} \\ m_a= \frac{51-14 \sqrt{2} +51+14 \sqrt{2} }{2} = \frac{102}{2} =51 \\ \\ m_g = \sqrt{(51-14 \sqrt{2} )(51+14 \sqrt{2} )} = \sqrt{2601-392} = \sqrt{2209} =47$