Question

afati numerele naturale x, pentru care fractia 17 supra x+7 sa fi supraunitara

Answer 1

[tex] \frac{17}{x+7}~subunitara \\ x+7<17 \\ x<10 \\ x \in \{0,1,2....9\} [/tex]

Answer 2

x+7<17 =>x<10 => x={0,1,2,3,4,5,6,7,8,9}
sper ca intelegi :}