Question

Află 2 la puterea 2016.
DAU COROANA!!!

Answer 1

$U(2^{1})=2$

$U(2^{2})=4$

$U(2^{3})=8$

$U(2^{4})=6$

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Si tot asa.

$U(2^{2016})=?$

2016:4=504 (rest 0)
=>2016=4×504=4×503+4

Am impartit la 4, pentru ca $U(2^{n})$ poate fi 2; 4; 6 sau 8 (in total 4 posibilitati)

$U(2^{2016})=U(2^{504*4+0})=U(2^{503*4+4})=U(2^{4})=6$