Question

afla 3 nr naturale stiind ca suma lor este 49,iar fiecare este egal cu jumatate din nr precedent.

Answer 1

a+b+c=49
b=a:2...=> a=2b
c=b:2...=> b=2c...=> a=4c

4c+2c+c=49
7c=49
c=49:7
c=7
b=7*2
b=14
a=14*2
a=28

28+14+7=49

Answer 2

[tex]a+ \frac{a}{2} + \frac{a}{4} = 49 [/tex]
$\frac{4a}{4} + \frac{2a}{4} + \frac{a}{4} = 49$
[tex] \frac{7a}{4} = 49 =\ \textgreater \ a = \frac{4*49}{7} = 4*7 = 28 a:2 = 14 a:4 = 7 [/tex]