Question

afla 3 nr pare consecutive,daca adunandu.le cu triplul sumei se obtine 528

Answer 1

(a+a+2+a+4)+3(a+a+2+a+4)=528
3a+6+3a+3a+6+3a+12=528
12a=528-6-6-12
a=504:12
a=42
nr sunt 42,44,46
42+44+46=132
132+3*132=132+396=528

sper sa iti fie de folos.