Question

Afla 3 nr pare consecutive, stiind ca, adunandu-le cu triplul sumei lor, se obt rezultatul 528.

Answer 1

( n + n+ 2+n + 4 ) + 3( n+ n+2+ n +4) = 528; 4( n+n+2+n+4)= 528; n+n+2+n+4= 132; 3n + 6= 132; 3n= 132-6=126 , n = 42; urmatorul nr n+2= 44, n+4= 46