Question

Afla 4 numere consecutive impare,stiind ca daca maresc cu 34 triplul sumei lor obtin 754.
Daca se poate,sa faceti cu a+b+c+d=

Answer 1

(a+b+c+d)×3+34=754
a=a+1
b=a+3
c=a+5
d=a+7
(a+1+a+3+a+5+a+7)×3+34=754
12×a+16×3+34=754
12×a+48+34=754
12×a=754-34-48
12×a=672
a=672÷12
a=56
=> a=56+1=57
=> b=56+3=59
=> c=56+5=61
=> d=56+7=63

proba:
(57+59+61+63)×3+34=754
240×3+34=754
720+34=754
754=754