Question

afla 6 nr pare consecutive ,stiind ca ,daca din suma lor scadem suma numerelor impare care se afla intre ele ,obtinand rezultatul 375.

Answer 1

suma  a 6 numere pare consecutive= a+a+2+a+4+a+6+a+8+a+10= 6a+30
suma nr imp aflate intre ele = a+1+a+3+a+5+a+7+a+9=5a+25

6a+30-5a-25=375
a=375-5
a=370

Answer 2

suma nr.pare
(a+2)+(a+4)+(a+6)+(a+8)+(a+10)+(a+12)=6a+42
suma nr.impare 
(a+3)+(a+5)+(a+7)+(a+9)+(a+11)=5a+35

(6a+42)-(5a+35)=375
6a+42-5a-35=375
a+7=375
a=375-7
a=368

6 numere pare consecutive
a+2=368+2=370
a+4=368+4=372
a+6=368+6=374
a+8=368+8=376
a+10=368+10=378
a+12=368+12=380