Question

afla cantitatea de HNO3 70% necesara pentru obtinerea a 2 t de trinitrotoluen,cu randament de 86%

Answer 1

C6H5-CH3 + 3HO-NO2 ==> (O2N)3-C6H2-CH3 + 3H2O

3*63kg HNO3.............................227kg trotil
x kg HNO3...................................2000kg trotil

x = 189*2000/227 = 1665,198kg HNO3 (mt)

86%........................1665,198 kg HNO3
100%..........................x kg

x = 1936,27kg

C=md/ms*100 => ms=md*100/C = 1936,27*100/70 = 2766,1 kg sol. HNO3