Question

afla nr. naturale care inpartite la 6 dau catul cu 2 mai mic decat restul . Dau coroana!

Answer 1

ab : 6 = c r r<6
c = r-2
ab = 6(r-2)+r
ab = 6×r-12+r
ab = 7×r-12

daca r = 3
ab = 7×3-12 = 21-12 = 9
9:6 = 1 rest 3
1 = 3-2

daca r=4
ab = 7×4-12 = 28-12 = 16
16:6 = 2 rest 4
2 = 4-2

daca r = 5
ab = 7×5-12 = 35-12 = 23
23:6 = 3 rest 5
3 = 5-2
Numerele sunt:
9; 16 ;23 .