Question

Afla nr. necunoscut:

232+[48×25+(540×a-82×5)×10]:100=797

(65+35):100-a:[6-5×(18-4×4):2]+0:3=0


Dau coroana !!

Answer 1

1.[48x25+(540xa-82x5)x10]:100=797-232
1200+(540xa-410)x10=565x100
(540xa-410)x10=56500-1200
540xa-410=55300:10
540xa=5530+410
540xa=5940
a=5940:540
a=11
 2. (65+35):100-a:[6-5×(18-4×4):2]+0:3=0nu se poate 0:35.3+3×{3+3×[3+3×(3+a:3)+3]+3}:3=633×{3+3×[3+3×(3+a:3)+3]+3}:3=63-33x{3+3×{3+3×[3+3×(3+a:3)+3]+3}:3=603×{3+3×[3+3×(3+a:3)+3]+3}=60x33×{3+3×[3+3×(3+a:3)+3]+3}=180{3+3×[3+3×(3+a:3)+3]+3}=180:33+3×[3+3×(3+a:3)+3]+3=603+3×[3+3×(3+a:3)+3]=60-33+3×[3+3×(3+a:3)+3]=573×[3+3×(3+a:3)+3]=57-33×[3+3×(3+a:3)+3]=54[3+3×(3+a:3)+3]=54:33+3×(3+a:3)+3=183+3x(3+a:3)=18-33+3x(3+a:3)=153x(3+a:3)=15-33x(3+a:3)=123+a:3=12:33+a:3=4a:3=4-3a:3=1a=1x3a=3