Question

afla nr necunoscut.a)101*(101-(101-102÷x)=202 b)369-(x+112)÷5+113)=434 c)104÷(x-3×8)×2÷8)=13

Answer 1

a) 101×[101-(101-102:2x)]=202
[101(101-102:x)]=202:101
[101-(101-102:x)]=2
(101-102:x)=101-2
(101-102:x)=99
102:x=101-99
102:x=2
x=102:2
x=51
b) 669-[(x+112):5+113]=434
[(x+112):5+113]=669-434
[(x+112:5+113]=235
[(x+112):5]=235-113
[x+112):5]=122
(x+112)=122×5
x+112=610
x=610-112
x=498
c) 104:(x-3×8)×2:8=13
(x-24)×2:8=104:13
(x-24)×2:8=8
(x-24)×2=8×8
(x-24)×2=64
(x-24)=64:2
x-24=32
x=32+24
x=58
b este gresita deoarece nu poți obții rezultatul bun!