Question

afla numaru necunoscu prin medota mersului invers:20×e-(1950+550):100=6175 ;35×f+(800-752:4):2=551;g:25+(100-1632:51)×2=286;244-h×5+(300-6×16):4=225

Answer 1

20e-(1950+550):100=6175
20e-2500:100=6175
20e-25=6175
20e=6175+25
20e=6200
e=6200:20
e=310
35f+(800-752:4):2=551
35f+(800-188):2=551
35f+612:2=551
35f+306=551
35f=551-306
35f=245
f=245:35
f=7
g:25+(100-1632:51)×2=286
g:25+(100-32)×2=286
g:25+68×2=286
g:25+136=286
g:25=286-136
g:25=150
g=150×25
g=3750
244-h×5+(300-6×16):4=225
244-h×5+(300-96):4=225
244-h×5+204:4=225
244-h×5+51=225
244-h×5=225-51
244-h×5=174
h×5=244-174
h×5=70
h=70:5
h=14