Matematică, întrebare adresată de CristiTube, 9 ani în urmă

Afla numarul necunoscut:
1) 955:A=4 rest 3
2) 30+{64:4+5x[2x(17:X)-10]}:2=98
3) {[(X-3)x2-1]x2-30}x3-40=500
4) 50+3x{[(10+260:C)x3+4]:4}-30=338

Răspunsuri la întrebare

Răspuns de predaen
4
1) 955:A=4 rest 3
955=4a+3
4a=955-3
4a=952
a=952:4
a=238

2) 30+{64:4+5x[2x(17:X)-10]}:2=98
{16+5x[2x(17:X)-10]}:2=98-30
{16+5x[2x(17:X)-10]}:2=68
{16+5x[2x(17:X)-10]}=68x2
16+5x[2x(17:X)-10]=136
5x[2x(17:X)-10]=136-16
5x[2x(17:X)-10]=120
[2x(17:X)-10]=120:5
2x(17:X)-10=24
2x(17:X)=24+10
2x(17:X)=34
17:X=34:2
17:X=17
x=17x17
x=289

3) {[(X-3)x2-1]x2-30}x3-40=500
{[(X-3)x2-1]x2-30}x3=500+40
{[(X-3)x2-1]x2-30}x3=540
{[(X-3)x2-1]x2-30}=540:3
[(X-3)x2-1]x2-30=180
[(X-3)x2-1]x2=180+30
[(X-3)x2-1]x2=210
[(X-3)x2-1]=210:2
(X-3)x2-1=105
(X-3)x2=105+1
(X-3)x2=106
(X-3)=106:2
X-3=53
x=53+3
x=56

4) 50+3x{[(10+260:C)x3+4]:4}-30=338
3x{[(10+260:C)x3+4]:4}=338-50+30
3x{[(10+260:C)x3+4]:4}=318
{[(10+260:C)x3+4]:4}=318:3
[(10+260:C)x3+4]:4=106
[(10+260:C)x3+4]=106x4
(10+260:C)x3+4=424
(10+260:C)x3=424-4
(10+260:C)x3=420
(10+260:C)=420:3
10+260:C=140
260:C=140-10
260:C=130
c=260:130
c=2







predaen: Succes !
CristiTube: Multumesc !
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