Află numărul necunoscut din:
41 x 100 – a = 32 : 4 x 50
bx 5 + 79 x 25 = 20 x 50 x 2
(49 : 7 + 3 x 25.- 81:9:3:3)+c= 100
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Salutare!
41×100-a=32:4×50
4 100-a=8×50
4 100-a=400
a=4 100-400
a=3 700
b×5+79×25=20×50×2
b×5+1 975=1 000×2
b×5+1 975=2 000
b×5=2000-1975
b×5=25
b=25:5
b=5
(49:7+3×25-81:9:3:3)+c=100
(7+75-9:3:3)+c=100
(7+75-3:3)+c=100
(7+75-1)+c=100
(82-1)+c=100
81+c=100
c=100-81
c=19
#Succes!
❀❀ೋ═══ • - • ═══ೋ❀❀
Explicație pas cu pas:
Bună !!
•Rezolvarea:
**mai jos↓
•41×100-a=32:4×50
•4100-a=8×50
•4100-a=400
•a=4100-400
•a=3700
*Verificare:
•41×100-3700=32:4×50
•4100-3700=8×50
•400=400 ✓✓
•b×5+79×25=20×50×2
•b×5+1975=1000×2
•b×5+1975=2000
•b×5=2000-1975
•b×5=25
•b=25:5
•b=5
*Verificare:
•5×5+79×25=20×50×2
•25+1975=1000×2
•2000=2000 ✓✓
•(49:7+3×25-81:9:3:3)+c=100
•(7+75-9:3:3)+c=100
•(82-3:3)+c=100
•(82-1)+c=100
•81+c=100
•c=100-81
•c=19
*Verificare:
•(49:7+3×25-81:9:3:3)+19=100
•(7+75-9:3:3)+19=100
•(82-3:3)+19=100
•(82-1)+19=100
•81+19=100
•100=100 ✓✓
Succes !!;)
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