Question

Afla numărul necunoscut prin metoda mersului invers: m+260:2*3+4*52=1985; 3*[8+2*(5*n+27:3)]=168
Multumesc!!!

Answer 1

m+260:2×3+4×52=1985
m+130×3+208=1985
m+390=1985-208
m+390=1777
m=1777-390
m =1387
Verificare:
m+260:2×3+4×52=1985
1387+390+208=1985

3×[8+2×(5×n+27:3)]=168
3×[8+2×(5×n+9)]=168
[8+2×(5×n+9)]=168:3
[8+2×(5×n+9)]=56
8+2×5×n+2×9=56
8+10×n+18=56
8+10×n=56-18
8+10×n=38
10×n=38-8
10×n=30
n=30:10
n=3
Verificare:
3×[8+2×(5×n+27:3)]=168
3×[8+2×(5×3+27:3)]=
3×[8+2×(15+9)]=
3×(8+2×24)=
3×(8+48)=
3×56=
168