Question

afla numerele a si b din egalitatile:
a) [(a +116:2)x 3 +4]x11=1991
b) (b:11-4) : 3 -110 :2 =4

Answer 1

a) [(a +116:2)x 3 +4]x11=1991
[(a +58)x 3 +4]=1991:11
(a +58)x 3 +4=181
(a +58)x 3=181-4
(a +58)x 3=177
a +58=177:3
a +58=59
a=59-58
a=1

 b) (b:11-4) : 3 -110 :2 =4
(b:11-4) : 3 - 55 =4
(b:11-4) : 3  =4 +55
(b:11-4) : 3  =59
b:11-4   =59x3
b:11-4   =177
b:11   =177+4
b:11   =181
b=1991