Question

afla numerele a si b,stiind ca:a+b=88 a-b=6 b)a+b=20 b-a=4 c)a+b=96 a:b=3 d)a-b=16 a:b=3

Answer 1

1) a+b=88
     a-b=6 =>  a=b+6
b  |__|
a  |__|+6|
88-6=82
82:2=41 (b)
41+6=47 (a)
verif: 41+47=88


2. a+b=20
b-a=4
b=a+4
a  |__|
b  |__|+4|
20-4=16
16:2=8 (a)
8+4=12 (b)


3. a+b=96
a:b=3  => a=bx3
b  |__|
a  |__|__|__|
96:4=24 (b)
24x3=72(a)

4. a-b=16
a:b=3  =. a=bx3
b  |__|
a  |__|__|__|
16:2=8 (b)
8x3=24(a)
v: 24-8=16

Answer 2

a)a+b=88 a-b=6
a=b+6
b+6+b=88
2b=88-6
2b=82
82:2=b=41
a=41+6=47
b)a+b=20
b-a=4
b=a+4
a+4+a=20
2a=20-4
2a=16
a=16:2=8
b=8+4=12
c)a+b=96
a:b=3
a=b×3=3b
3b+b=96
4b=96
b=96:4=24
b=24
a=24×3=72
a-b=16
a:b=3
a=b×3=3b
3b-b=16
2b=16
b=16:2=8
a=8×3=24