Question

Afla numerele necunoscute:
a.(x+20):12+68=78
b.(x+282-75):2=104
c.x ×4:10+101=133

Answer 1

a. ( x + 20 ) : 12 + 68 = 78

( x + 20 ) : 12 = 78 - 68

( x + 20 ) : 12 = 10

( x + 20 ) = 10 × 12

x + 20 = 120

x = 120 - 120

x = 100

b . ( x + 282 - 75 ) : 2 = 104

( x + 207 ) : 2 = 104

( x + 207 ) = 104 × 2

x + 207 = 208

x = 208 - 207

x = 1

c. x × 4 : 10 + 101 = 133

x × 4 : 10 = 133 - 101

x × 4 : 10 = 32

x × 4 = 32 × 10

x × 4 = 320

x = 320 : 4

x = 80

Answer 2

a.
(x+20):12+68=78
(x+20):12=78-68
(x+20):12=10
x+20=10×12
x+20=120
x=120-20
x=100


b.
(x+282-75):2=104
x+282-75=104×2
x+282-75=208
x+282=208+75
x+282=283
x=283-282
x=1


c.
x ×4:10+101=133
x ×4:10=133-101
x ×4:10=32
x ×4=32×10
x ×4=320
x = 320 : 4
x = 80