Question

Afla perechile de numere naturale (a,b) care satisfac simultan egalitatiile:
a+a=b
axa=b

Answer 1

a=2;b=4 perechea(2,4) 2+2=4;2×2=4.

Answer 2

b=2a;
b=a²;
⇒2a=a²⇒a=2⇒2·2=4=2²;
⇒a=2;
⇒b=2·2⇒b=4;
sau b=a²⇒b=2²⇒b=4;