Question

afla sum nr a si b stiind ca a+116÷2=(1991÷11-4)÷3 si b÷11-4=(4+110÷2)×3

Answer 1

a+116:2=(1991:11-4):3
a+58=(181-4):3
a+58=177:3
a+58=59
a=59-58
a=1

b:11-4=(4+110:2)x3
b:11-4=(4+55)x3
b:11-4=59x3
b:11-4=177
b:11=177+4
b:11=181
b=181x11
b=1991

a+b=1+1991=1992