Question

afla suma numerelor ași b știind ca :a+116:2=(1991÷11-4)și b÷11-4=(4+110÷2)×3=

Answer 1

a+116:2=(1991:11-4):3
a+58=(181-4):3
a+58=177:3
a+58=59
a=59-58
a=1
b:11-4=(4+110:2)*3
b:11-4=(4+55)*3
b:11-4=59*3
b:11-4=177
b:11=177+4
b:11=181
b=181*11
b=1991